8/(4-2x)+6=10

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Solution for 8/(4-2x)+6=10 equation: 



8/(4-2x)+6=10

We move all terms to the left:

8/(4-2x)+6-(10)=0



Domain of the equation: (4-2x)!=0

We move all terms containing x to the left, all other terms to the right

-2x!=-4

x!=-4/-2

x!=+2

x∈R



We add all the numbers together, and all the variables

8/(-2x+4)+6-10=0

We add all the numbers together, and all the variables

8/(-2x+4)-4=0

We multiply all the terms by the denominator


-4*(-2x+4)+8=0

We multiply parentheses

8x-16+8=0

We add all the numbers together, and all the variables

8x-8=0

We move all terms containing x to the left, all other terms to the right

8x=8

x=8/8

x=1

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