8/(4-x)-2-8/(2+x)=0

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Solution for 8/(4-x)-2-8/(2+x)=0 equation: 


D( x )

x+2 = 0

4-x = 0

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

4-x = 0

4-x = 0

4-x = 0 // - 4

-x = -4 // * -1

x = 4

x in (-oo:-2) U (-2:4) U (4:+oo)

8/(4-x)-(8/(x+2))-2 = 0

8/(4-x)-8*(x+2)^-1-2 = 0

8/(4-x)-8/(x+2)-2 = 0

(8*(x+2))/((4-x)*(x+2))+(-8*(4-x))/((4-x)*(x+2))+(-2*(4-x)*(x+2))/((4-x)*(x+2)) = 0

8*(x+2)-8*(4-x)-2*(4-x)*(x+2) = 0

2*x^2+16*x-4*x-16-16 = 0

2*x^2+12*x-32 = 0

2*x^2+12*x-32 = 0

2*(x^2+6*x-16) = 0

x^2+6*x-16 = 0

DELTA = 6^2-(-16*1*4)

DELTA = 100

DELTA > 0

x = (100^(1/2)-6)/(1*2) or x = (-100^(1/2)-6)/(1*2)

x = 2 or x = -8

2*(x+8)*(x-2) = 0

(2*(x+8)*(x-2))/((4-x)*(x+2)) = 0

(2*(x+8)*(x-2))/((4-x)*(x+2)) = 0 // * (4-x)*(x+2)

2*(x+8)*(x-2) = 0

( x+8 )

x+8 = 0 // - 8

x = -8

( x-2 )

x-2 = 0 // + 2

x = 2

x in { -8, 2 }

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