8/(b+10)=4/(2b-7)

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Solution for 8/(b+10)=4/(2b-7) equation: 


D( b )

2*b-7 = 0

b+10 = 0

2*b-7 = 0

2*b-7 = 0

2*b-7 = 0 // + 7

2*b = 7 // : 2

b = 7/2

b+10 = 0

b+10 = 0

b+10 = 0 // - 10

b = -10

b in (-oo:-10) U (-10:7/2) U (7/2:+oo)

8/(b+10) = 4/(2*b-7) // - 4/(2*b-7)

8/(b+10)-(4/(2*b-7)) = 0

8/(b+10)-4*(2*b-7)^-1 = 0

8/(b+10)-4/(2*b-7) = 0

(8*(2*b-7))/((b+10)*(2*b-7))+(-4*(b+10))/((b+10)*(2*b-7)) = 0

8*(2*b-7)-4*(b+10) = 0

12*b-96 = 0

(12*b-96)/((b+10)*(2*b-7)) = 0

(12*b-96)/((b+10)*(2*b-7)) = 0 // * (b+10)*(2*b-7)

12*b-96 = 0

12*b-96 = 0 // + 96

12*b = 96 // : 12

b = 96/12

b = 8

b = 8

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