8/(n+4)=4/n

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Solution for 8/(n+4)=4/n equation: 



8/(n+4)=4/n

We move all terms to the left:

8/(n+4)-(4/n)=0



Domain of the equation: (n+4)!=0

We move all terms containing n to the left, all other terms to the right

n!=-4

n∈R





Domain of the equation: n)!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

8/(n+4)-(+4/n)=0

We get rid of parentheses

8/(n+4)-4/n=0

We calculate fractions


8n/(n^2+4n)+(-4n-16)/(n^2+4n)=0

We multiply all the terms by the denominator


8n+(-4n-16)=0

We get rid of parentheses

8n-4n-16=0

We add all the numbers together, and all the variables

4n-16=0

We move all terms containing n to the left, all other terms to the right

4n=16

n=16/4

n=4

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