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8/(x+3)=2/x
We move all terms to the left:
8/(x+3)-(2/x)=0
Domain of the equation: (x+3)!=0
We move all terms containing x to the left, all other terms to the right
x!=-3
x∈R
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
8/(x+3)-(+2/x)=0
We get rid of parentheses
8/(x+3)-2/x=0
We calculate fractions
8x/(x^2+3x)+(-2x-6)/(x^2+3x)=0
We multiply all the terms by the denominator
8x+(-2x-6)=0
We get rid of parentheses
8x-2x-6=0
We add all the numbers together, and all the variables
6x-6=0
We move all terms containing x to the left, all other terms to the right
6x=6
x=6/6
x=1
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