8/(x+4)=6/(x-4)

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Solution for 8/(x+4)=6/(x-4) equation: 



8/(x+4)=6/(x-4)

We move all terms to the left:

8/(x+4)-(6/(x-4))=0



Domain of the equation: (x+4)!=0

We move all terms containing x to the left, all other terms to the right

x!=-4

x∈R





Domain of the equation: (x-4))!=0

x∈R



We calculate fractions


8x/((x+4)*(x-4)))+(-(6*(x+4))/((x+4)*(x-4)))=0



We calculate terms in parentheses: -(6*(x+4))/((x+4)*(x-4))), so:

6*(x+4))/((x+4)*(x-4))

We multiply all the terms by the denominator


6*(x+4))

We multiply parentheses

6x+

We add all the numbers together, and all the variables

6x

Back to the equation:

-(6x)



We add all the numbers together, and all the variables

-6x+8x/((x+4)*(x-4)))+(=0

We multiply all the terms by the denominator


-6x*((x+4)*(x-4)))+(+8x=0

We add all the numbers together, and all the variables

8x-6x*((x+4)*(x-4)))+(=0

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