8/(x-3)-1/(10)=32/(4x-12)

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Solution for 8/(x-3)-1/(10)=32/(4x-12) equation:


D( x )

4*x-12 = 0

x-3 = 0

4*x-12 = 0

4*x-12 = 0

4*x-12 = 0 // + 12

4*x = 12 // : 4

x = 12/4

x = 3

x-3 = 0

x-3 = 0

x-3 = 0 // + 3

x = 3

x in (-oo:3) U (3:+oo)

8/(x-3)-(1/10) = 32/(4*x-12) // - 32/(4*x-12)

8/(x-3)-(32/(4*x-12))-(1/10) = 0

8/(x-3)-32*(4*x-12)^-1-1/10 = 0

8/(x-3)-32/(4*x-12)-1/10 = 0

(8*10*(4*x-12))/(10*(x-3)*(4*x-12))+(-32*10*(x-3))/(10*(x-3)*(4*x-12))+(-1*(x-3)*(4*x-12))/(10*(x-3)*(4*x-12)) = 0

8*10*(4*x-12)-32*10*(x-3)-1*(x-3)*(4*x-12) = 0

24*x-4*x^2-36 = 0

24*x-4*x^2-36 = 0

4*(6*x-x^2-9) = 0

6*x-x^2-9 = 0

DELTA = 6^2-(-9*(-1)*4)

DELTA = 0

x = -6/(-1*2)

x = 3 or x = 3

4*(x-3)^2 = 0

(4*(x-3)^2)/(10*(x-3)*(4*x-12)) = 0

(4*(x-3)^2)/(10*(x-3)*(4*x-12)) = 0 // * 10*(x-3)*(4*x-12)

4*(x-3)^2 = 0

x-3 = 0 // + 3

x = 3

x in { 3}

x belongs to the empty set

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