8/(x-3)-1/10=32/(4(x-3))

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Solution for 8/(x-3)-1/10=32/(4(x-3)) equation: 


D( x )

4*(x-3) = 0

x-3 = 0

4*(x-3) = 0

4*(x-3) = 0

x-3 = 0 // + 3

x = 3

x-3 = 0

x-3 = 0

x-3 = 0 // + 3

x = 3

x in (-oo:3) U (3:+oo)

8/(x-3)-(1/10) = 32/(4*(x-3)) // - 32/(4*(x-3))

8/(x-3)-(32/(4*(x-3)))-(1/10) = 0

8/(x-3)-8*(x-3)^-1-1/10 = 0

8/(x-3)-8/(x-3)-1/10 = 0

(8*10)/(10*(x-3))+(-8*10)/(10*(x-3))+(-1*(x-3))/(10*(x-3)) = 0

8*10-1*(x-3)-8*10 = 0

3-x = 0

(3-x)/(10*(x-3)) = 0

(3-x)/(10*(x-3)) = 0 // * 10*(x-3)

3-x = 0

3-x = 0 // - 3

-x = -3 // * -1

x = 3

x in { 3} 

x belongs to the empty set

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