8/2(5-3)x10-5x2

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Solution for 8/2(5-3)x10-5x2 equation: 


x in (-oo:+oo)

(8/2)*(5-3)*x^10-(5*x^2) = 0

(8/2)*(5-3)*x^10-5*x^2 = 0

8*x^10-5*x^2 = 0

t_1 = x^2

8*t_1^5-5*t_1^1 = 0

8*t_1^5-5*t_1 = 0

t_1*(8*t_1^4-5) = 0

8*t_1^4 = 5 // : 8

t_1^4 = 5/8

t_1^4 = 5/8 // ^ 1/4

abs(t_1) = (5/8)^(1/4)

t_1 = (5/8)^(1/4) or t_1 = -(5/8)^(1/4)

t_1 = 0

t_1 = 0

t_1 = (5/8)^(1/4)

x^2-(5/8)^(1/4) = 0

1*x^2 = (5/8)^(1/4) // : 1

x^2 = (5/8)^(1/4)

x^2 = (5/8)^(1/4) // ^ 1/2

abs(x) = (5/8)^(1/8)

x = (5/8)^(1/8) or x = -(5/8)^(1/8)

t_1 = -(5/8)^(1/4)

x^2+(5/8)^(1/4) = 0

1*x^2 = -(5/8)^(1/4) // : 1

x^2 = -(5/8)^(1/4)

t_1 = 0

x^2+0 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in { (5/8)^(1/8), -(5/8)^(1/8), 0 }

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