8/28=40/y

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Solution for 8/28=40/y equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

8/28 = 40/y // - 40/y

8/28-(40/y) = 0

8/28-40*y^-1 = 0

-40*y^-1 = -2/7 // : -40

y^-1 = 1/140

-1 < 0

1/(y^1) = 1/140 // * y^1

1 = 1/140*y^1 // : 1/140

140 = y^1

y = 140

y = 140

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