8/2x+5=3/5x-2

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Solution for 8/2x+5=3/5x-2 equation:



8/2x+5=3/5x-2
We move all terms to the left:
8/2x+5-(3/5x-2)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 5x-2)!=0
x∈R
We get rid of parentheses
8/2x-3/5x+2+5=0
We calculate fractions
40x/10x^2+(-6x)/10x^2+2+5=0
We add all the numbers together, and all the variables
40x/10x^2+(-6x)/10x^2+7=0
We multiply all the terms by the denominator
40x+(-6x)+7*10x^2=0
Wy multiply elements
70x^2+40x+(-6x)=0
We get rid of parentheses
70x^2+40x-6x=0
We add all the numbers together, and all the variables
70x^2+34x=0
a = 70; b = 34; c = 0;
Δ = b2-4ac
Δ = 342-4·70·0
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-34}{2*70}=\frac{-68}{140} =-17/35 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+34}{2*70}=\frac{0}{140} =0 $

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