8/3(x-1)-8=4(1+x)+5

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Solution for 8/3(x-1)-8=4(1+x)+5 equation:



8/3(x-1)-8=4(1+x)+5
We move all terms to the left:
8/3(x-1)-8-(4(1+x)+5)=0
Domain of the equation: 3(x-1)!=0
x∈R
We add all the numbers together, and all the variables
8/3(x-1)-(4(x+1)+5)-8=0
We multiply all the terms by the denominator
-((4(x+1)+5))*3(x-1)-8*3(x-1)+8=0
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
Wy multiply elements
-((4(x+1)+5))*3(x-1)-24x(x+8=0
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1
We calculate terms in parentheses: -((4(x+1)+5))*3(x-1), so:
(4(x+1)+5))*3(x-1

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