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8/3+x=4+1/3x
We move all terms to the left:
8/3+x-(4+1/3x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-(1/3x+4)+8/3=0
We get rid of parentheses
x-1/3x-4+8/3=0
We calculate fractions
x-4=0
We move all terms containing x to the left, all other terms to the right
x=4
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