8/3x+2/6x=48/9

Solution for 8/3x+2/6x=48/9 equation:

8/3x+2/6x=48/9

We move all terms to the left:

8/3x+2/6x-(48/9)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 6x!=0

x!=0/6

x!=0

x∈R


We add all the numbers together, and all the variables

8/3x+2/6x-(+48/9)=0

We get rid of parentheses

8/3x+2/6x-48/9=0

We calculate fractions


(-5184x^2)/1458x^2+3888x/1458x^2+486x/1458x^2=0

We multiply all the terms by the denominator


(-5184x^2)+3888x+486x=0

We add all the numbers together, and all the variables

(-5184x^2)+4374x=0

We get rid of parentheses

-5184x^2+4374x=0

a = -5184; b = 4374; c = 0;
Δ = b2-4ac
Δ = 43742-4·(-5184)·0
Δ = 19131876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19131876}=4374$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4374)-4374}{2*-5184}=\frac{-8748}{-10368}
=27/32
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4374)+4374}{2*-5184}=\frac{0}{-10368}
=0
$