8/3x+5+2(1+4x)=103

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Solution for 8/3x+5+2(1+4x)=103 equation:


x in (-oo:+oo)

2*(4*x+1)+(8/3)*x+5 = 103 // - 103

2*(4*x+1)+(8/3)*x-103+5 = 0

2*(4*x+1)+(8*x)/3-103+5 = 0

(2*3*(4*x+1))/3+(8*x)/3+(-103*3)/3+(3*5)/3 = 0

2*3*(4*x+1)+8*x-103*3+3*5 = 0

32*x-309+6+15 = 0

32*x-303+15 = 0

32*x-288 = 0

(32*x-288)/3 = 0

(32*x-288)/3 = 0 // * 3

32*x-288 = 0

32*x-288 = 0 // + 288

32*x = 288 // : 32

x = 288/32

x = 9

x = 9

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