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8/3x-10=x
We move all terms to the left:
8/3x-10-(x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
-1x+8/3x-10=0
We multiply all the terms by the denominator
-1x*3x-10*3x+8=0
Wy multiply elements
-3x^2-30x+8=0
a = -3; b = -30; c = +8;
Δ = b2-4ac
Δ = -302-4·(-3)·8
Δ = 996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{996}=\sqrt{4*249}=\sqrt{4}*\sqrt{249}=2\sqrt{249}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{249}}{2*-3}=\frac{30-2\sqrt{249}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{249}}{2*-3}=\frac{30+2\sqrt{249}}{-6} $
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