8/3y+8/6y=2

Solution for 8/3y+8/6y=2 equation:

8/3y+8/6y=2

We move all terms to the left:

8/3y+8/6y-(2)=0


Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R



Domain of the equation: 6y!=0

y!=0/6

y!=0

y∈R


We calculate fractions


48y/18y^2+24y/18y^2-2=0

We multiply all the terms by the denominator


48y+24y-2*18y^2=0

We add all the numbers together, and all the variables

72y-2*18y^2=0

Wy multiply elements

-36y^2+72y=0

a = -36; b = 72; c = 0;
Δ = b2-4ac
Δ = 722-4·(-36)·0
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-72}{2*-36}=\frac{-144}{-72}
=+2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+72}{2*-36}=\frac{0}{-72}
=0
$