8/3y-8y=0

Solution for 8/3y-8y=0 equation:

8/3y-8y=0


Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R


We add all the numbers together, and all the variables

-8y+8/3y=0

We multiply all the terms by the denominator


-8y*3y+8=0

Wy multiply elements

-24y^2+8=0

a = -24; b = 0; c = +8;
Δ = b2-4ac
Δ = 02-4·(-24)·8
Δ = 768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{768}=\sqrt{256*3}=\sqrt{256}*\sqrt{3}=16\sqrt{3}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{3}}{2*-24}=\frac{0-16\sqrt{3}}{-48}
=-\frac{16\sqrt{3}}{-48}
=-\frac{\sqrt{3}}{-3}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{3}}{2*-24}=\frac{0+16\sqrt{3}}{-48}
=\frac{16\sqrt{3}}{-48}
=\frac{\sqrt{3}}{-3}
$