8/4c-2=2/3c-12

Solution for 8/4c-2=2/3c-12 equation:

8/4c-2=2/3c-12

We move all terms to the left:

8/4c-2-(2/3c-12)=0


Domain of the equation: 4c!=0

c!=0/4

c!=0

c∈R



Domain of the equation: 3c-12)!=0

c∈R


We get rid of parentheses

8/4c-2/3c+12-2=0

We calculate fractions


24c/12c^2+(-8c)/12c^2+12-2=0

We add all the numbers together, and all the variables

24c/12c^2+(-8c)/12c^2+10=0

We multiply all the terms by the denominator


24c+(-8c)+10*12c^2=0

Wy multiply elements

120c^2+24c+(-8c)=0

We get rid of parentheses

120c^2+24c-8c=0

We add all the numbers together, and all the variables

120c^2+16c=0

a = 120; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·120·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*120}=\frac{-32}{240}
=-2/15
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*120}=\frac{0}{240}
=0
$