8/4x+8/8x=36/12

Solution for 8/4x+8/8x=36/12 equation:

8/4x+8/8x=36/12

We move all terms to the left:

8/4x+8/8x-(36/12)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R


We add all the numbers together, and all the variables

8/4x+8/8x-3=0

We calculate fractions


64x/32x^2+32x/32x^2-3=0

We multiply all the terms by the denominator


64x+32x-3*32x^2=0

We add all the numbers together, and all the variables

96x-3*32x^2=0

Wy multiply elements

-96x^2+96x=0

a = -96; b = 96; c = 0;
Δ = b2-4ac
Δ = 962-4·(-96)·0
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-96}{2*-96}=\frac{-192}{-192}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+96}{2*-96}=\frac{0}{-192}
=0
$