8/4x+x=63

Solution for 8/4x+x=63 equation:

8/4x+x=63

We move all terms to the left:

8/4x+x-(63)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We add all the numbers together, and all the variables

x+8/4x-63=0

We multiply all the terms by the denominator


x*4x-63*4x+8=0

Wy multiply elements

4x^2-252x+8=0

a = 4; b = -252; c = +8;
Δ = b2-4ac
Δ = -2522-4·4·8
Δ = 63376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{63376}=\sqrt{16*3961}=\sqrt{16}*\sqrt{3961}=4\sqrt{3961}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-252)-4\sqrt{3961}}{2*4}=\frac{252-4\sqrt{3961}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-252)+4\sqrt{3961}}{2*4}=\frac{252+4\sqrt{3961}}{8}
$