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8/4x-8-6/3x-6=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
8/4x-6/3x-14=0
We calculate fractions
24x/12x^2+(-24x)/12x^2-14=0
We multiply all the terms by the denominator
24x+(-24x)-14*12x^2=0
Wy multiply elements
-168x^2+24x+(-24x)=0
We get rid of parentheses
-168x^2+24x-24x=0
We add all the numbers together, and all the variables
-168x^2=0
a = -168; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-168)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-336}=0$
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