8/5(z-6)=-1/5(2z+3)

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Solution for 8/5(z-6)=-1/5(2z+3) equation: 



8/5(z-6)=-1/5(2z+3)

We move all terms to the left:

8/5(z-6)-(-1/5(2z+3))=0



Domain of the equation: 5(z-6)!=0

z∈R





Domain of the equation: 5(2z+3))!=0

z∈R



We calculate fractions


(40z2/(5(z-6)*5(2z+3)))+(-(-5zz)/(5(z-6)*5(2z+3)))=0



We calculate terms in parentheses: +(40z2/(5(z-6)*5(2z+3))), so:

40z2/(5(z-6)*5(2z+3))

We multiply all the terms by the denominator


40z2

We add all the numbers together, and all the variables

40z^2

Back to the equation:

+(40z^2)





We calculate terms in parentheses: +(-(-5zz)/(5(z-6)*5(2z+3))), so:

-(-5zz)/(5(z-6)*5(2z+3))

We multiply all the terms by the denominator


-(-5zz)

We get rid of parentheses

5zz

Back to the equation:

+(5zz)

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