8/5k+2/6k=k-1/2=

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Solution for 8/5k+2/6k=k-1/2= equation:



8/5k+2/6k=k-1/2=
We move all terms to the left:
8/5k+2/6k-(k-1/2)=0
Domain of the equation: 5k!=0
k!=0/5
k!=0
k∈R
Domain of the equation: 6k!=0
k!=0/6
k!=0
k∈R
We add all the numbers together, and all the variables
8/5k+2/6k-(+k-1/2)=0
We get rid of parentheses
8/5k+2/6k-k+1/2=0
We calculate fractions
180k^2/120k^2-k+192k/120k^2+40k/120k^2=0
We add all the numbers together, and all the variables
180k^2/120k^2-1k+192k/120k^2+40k/120k^2=0
We multiply all the terms by the denominator
180k^2-1k*120k^2+192k+40k=0
We add all the numbers together, and all the variables
180k^2+232k-1k*120k^2=0
Wy multiply elements
180k^2-120k^3+232k=0
We do not support ekpression: k^3

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