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8/5x+1/10x=50/15
We move all terms to the left:
8/5x+1/10x-(50/15)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 10x!=0We add all the numbers together, and all the variables
x!=0/10
x!=0
x∈R
8/5x+1/10x-(+50/15)=0
We get rid of parentheses
8/5x+1/10x-50/15=0
We calculate fractions
(-2500x^2)/750x^2+1200x/750x^2+75x/750x^2=0
We multiply all the terms by the denominator
(-2500x^2)+1200x+75x=0
We add all the numbers together, and all the variables
(-2500x^2)+1275x=0
We get rid of parentheses
-2500x^2+1275x=0
a = -2500; b = 1275; c = 0;
Δ = b2-4ac
Δ = 12752-4·(-2500)·0
Δ = 1625625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1625625}=1275$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1275)-1275}{2*-2500}=\frac{-2550}{-5000} =51/100 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1275)+1275}{2*-2500}=\frac{0}{-5000} =0 $
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