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8/5x+9=x
We move all terms to the left:
8/5x+9-(x)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
-1x+8/5x+9=0
We multiply all the terms by the denominator
-1x*5x+9*5x+8=0
Wy multiply elements
-5x^2+45x+8=0
a = -5; b = 45; c = +8;
Δ = b2-4ac
Δ = 452-4·(-5)·8
Δ = 2185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-\sqrt{2185}}{2*-5}=\frac{-45-\sqrt{2185}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+\sqrt{2185}}{2*-5}=\frac{-45+\sqrt{2185}}{-10} $
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