8/5x=40x=

Solution for 8/5x=40x= equation:

8/5x=40x=

We move all terms to the left:

8/5x-(40x)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R


We add all the numbers together, and all the variables

-40x+8/5x=0

We multiply all the terms by the denominator


-40x*5x+8=0

Wy multiply elements

-200x^2+8=0

a = -200; b = 0; c = +8;
Δ = b2-4ac
Δ = 02-4·(-200)·8
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80}{2*-200}=\frac{-80}{-400}
=1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80}{2*-200}=\frac{80}{-400}
=-1/5
$