8/9(3i+27)=2/9i+68

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Solution for 8/9(3i+27)=2/9i+68 equation: 


i in (-oo:+oo)

(8/9)*(3*i+27) = (2/9)*i+68 // - (2/9)*i+68

(8/9)*(3*i+27)-((2/9)*i)-68 = 0

(8/9)*(3*i+27)+(-2/9)*i-68 = 0

8/9*(3*i+27)+(-2*i)/9-68 = 0

(8/9*9*(3*i+27))/9+(-2*i)/9+(-68*9)/9 = 0

8/9*9*(3*i+27)-2*i-68*9 = 0

22*i-612+216 = 0

22*i-396 = 0

(22*i-396)/9 = 0

(22*i-396)/9 = 0 // * 9

22*i-396 = 0

22*i-396 = 0 // + 396

22*i = 396 // : 22

i = 396/22

i = 18

i = 18

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