8/9(3i+27)=2/9i=69

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Solution for 8/9(3i+27)=2/9i=69 equation: 



8/9(3i+27)=2/9i=69

We move all terms to the left:

8/9(3i+27)-(2/9i)=0



Domain of the equation: 9(3i+27)!=0

i∈R





Domain of the equation: 9i)!=0

i!=0/1

i!=0

i∈R



We add all the numbers together, and all the variables

8/9(3i+27)-(+2/9i)=0

We get rid of parentheses

8/9(3i+27)-2/9i=0

We calculate fractions


72i/(243i^2+2187i)+(-18i3/(243i^2+2187i)=0



We calculate terms in parentheses: +(-18i3/(243i^2+2187i), so:

-18i3/(243i^2+2187i

We multiply all the terms by the denominator


-18i3

We add all the numbers together, and all the variables

-18i^3

We do not support eipression: i^3

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