8/9(3t+5)=2/3(t-12)

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Solution for 8/9(3t+5)=2/3(t-12) equation: 



8/9(3t+5)=2/3(t-12)

We move all terms to the left:

8/9(3t+5)-(2/3(t-12))=0



Domain of the equation: 9(3t+5)!=0

t∈R





Domain of the equation: 3(t-12))!=0

t∈R



We calculate fractions


(24tt/(9(3t+5)*3(t-12)))+(-18t3/(9(3t+5)*3(t-12)))=0



We calculate terms in parentheses: +(24tt/(9(3t+5)*3(t-12))), so:

24tt/(9(3t+5)*3(t-12))

We multiply all the terms by the denominator


24tt

Back to the equation:

+(24tt)





We calculate terms in parentheses: +(-18t3/(9(3t+5)*3(t-12))), so:

-18t3/(9(3t+5)*3(t-12))

We multiply all the terms by the denominator


-18t3

We add all the numbers together, and all the variables

-18t^3

We do not support etpression: t^3

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