8/9(54x-36)+2=-3/4(-40+16x)

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Solution for 8/9(54x-36)+2=-3/4(-40+16x) equation:



8/9(54x-36)+2=-3/4(-40+16x)
We move all terms to the left:
8/9(54x-36)+2-(-3/4(-40+16x))=0
Domain of the equation: 9(54x-36)!=0
x∈R
Domain of the equation: 4(-40+16x))!=0
x∈R
We add all the numbers together, and all the variables
8/9(54x-36)-(-3/4(16x-40))+2=0
We calculate fractions
(32x1/(9(54x-36)*4(16x-40)))+(-(-27x5)/(9(54x-36)*4(16x-40)))+2=0
We calculate terms in parentheses: +(32x1/(9(54x-36)*4(16x-40))), so:
32x1/(9(54x-36)*4(16x-40))
We multiply all the terms by the denominator
32x1
We add all the numbers together, and all the variables
32x
Back to the equation:
+(32x)
We calculate terms in parentheses: +(-(-27x5)/(9(54x-36)*4(16x-40))), so:
-(-27x5)/(9(54x-36)*4(16x-40))
We add all the numbers together, and all the variables
-(-27x^5)/(9(54x-36)*4(16x-40))
We multiply all the terms by the denominator
-(-27x^5)
We do not support expression: x^5

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