8/9(54x-36)+2=3/4(-40+16x)

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Solution for 8/9(54x-36)+2=3/4(-40+16x) equation: 



8/9(54x-36)+2=3/4(-40+16x)

We move all terms to the left:

8/9(54x-36)+2-(3/4(-40+16x))=0



Domain of the equation: 9(54x-36)!=0

x∈R





Domain of the equation: 4(-40+16x))!=0

x∈R



We add all the numbers together, and all the variables

8/9(54x-36)-(3/4(16x-40))+2=0

We calculate fractions


(32x1/(9(54x-36)*4(16x-40)))+(-27x5/(9(54x-36)*4(16x-40)))+2=0



We calculate terms in parentheses: +(32x1/(9(54x-36)*4(16x-40))), so:

32x1/(9(54x-36)*4(16x-40))

We multiply all the terms by the denominator


32x1

We add all the numbers together, and all the variables

32x

Back to the equation:

+(32x)





We calculate terms in parentheses: +(-27x5/(9(54x-36)*4(16x-40))), so:

-27x5/(9(54x-36)*4(16x-40))

We multiply all the terms by the denominator


-27x5

We add all the numbers together, and all the variables

-27x^5

We do not support expression: x^5

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