8/9(54z-36)+2=-3/4(-40+16)+90

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Solution for 8/9(54z-36)+2=-3/4(-40+16)+90 equation: 



8/9(54z-36)+2=-3/4(-40+16)+90

We move all terms to the left:

8/9(54z-36)+2-(-3/4(-40+16)+90)=0



Domain of the equation: 9(54z-36)!=0

z∈R



We add all the numbers together, and all the variables

8/9(54z-36)+2-(-3/4(-24)+90)=0

We calculate fractions


()/(9(54z-36)*4(-24))+(-(-27z5)/(9(54z-36)*4(-24))+2=0



We calculate terms in parentheses: +()/(9(54z-36)*4(-24)), so:

)/(9(54z-36)*4(-24)

We multiply all the terms by the denominator


)

We add all the numbers together, and all the variables



Back to the equation:

+()



We add all the numbers together, and all the variables

(-(-27z^5)/(9(54z-36)*4(-24))+2+()=0

We multiply all the terms by the denominator


(-(-27z^5)=0



We calculate terms in parentheses: +(-(-27z^5), so:

-(-27z^5

We do not support ezpression: z^5

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