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8/9n-3=4/9(2n-3
We move all terms to the left:
8/9n-3-(4/9(2n-3)=0
Domain of the equation: 9n!=0
n!=0/9
n!=0
n∈R
Domain of the equation: 9(2n-3)-3!=0We calculate fractions
We move all terms containing n to the left, all other terms to the right
9(2n-3)!=3
n∈R
(72n(2-3)/(81n^2(2-3)+(-(4*9n)/(81n^2(2-3)=0
We calculate terms in parentheses: +(72n(2-3)/(81n^2(2-3)+(-(4*9n)/(81n^2(2-3), so:
72n(2-3)/(81n^2(2-3)+(-(4*9n)/(81n^2(2-3
We can not solve this equation
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