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8/9r+5/6r=62
We move all terms to the left:
8/9r+5/6r-(62)=0
Domain of the equation: 9r!=0
r!=0/9
r!=0
r∈R
Domain of the equation: 6r!=0We calculate fractions
r!=0/6
r!=0
r∈R
48r/54r^2+45r/54r^2-62=0
We multiply all the terms by the denominator
48r+45r-62*54r^2=0
We add all the numbers together, and all the variables
93r-62*54r^2=0
Wy multiply elements
-3348r^2+93r=0
a = -3348; b = 93; c = 0;
Δ = b2-4ac
Δ = 932-4·(-3348)·0
Δ = 8649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8649}=93$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(93)-93}{2*-3348}=\frac{-186}{-6696} =1/36 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(93)+93}{2*-3348}=\frac{0}{-6696} =0 $
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