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8/9x=6-2/3x
We move all terms to the left:
8/9x-(6-2/3x)=0
Domain of the equation: 9x!=0
x!=0/9
x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
8/9x-(-2/3x+6)=0
We get rid of parentheses
8/9x+2/3x-6=0
We calculate fractions
24x/27x^2+18x/27x^2-6=0
We multiply all the terms by the denominator
24x+18x-6*27x^2=0
We add all the numbers together, and all the variables
42x-6*27x^2=0
Wy multiply elements
-162x^2+42x=0
a = -162; b = 42; c = 0;
Δ = b2-4ac
Δ = 422-4·(-162)·0
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-42}{2*-162}=\frac{-84}{-324} =7/27 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+42}{2*-162}=\frac{0}{-324} =0 $
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