8/b+10=4-2b-7

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Solution for 8/b+10=4-2b-7 equation: 


D( b )

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

8/b+10 = 4-(2*b)-7 // - 4-(2*b)-7

2*b+8/b-4+7+10 = 0

2*b^1+8*b^-1+13*b^0 = 0

(2*b^2+13*b^1+8*b^0)/(b^1) = 0 // * b^2

b^1*(2*b^2+13*b^1+8*b^0) = 0

b^1

2*b^2+13*b+8 = 0

2*b^2+13*b+8 = 0

DELTA = 13^2-(2*4*8)

DELTA = 105

DELTA > 0

b = (105^(1/2)-13)/(2*2) or b = (-105^(1/2)-13)/(2*2)

b = (105^(1/2)-13)/4 or b = (-(105^(1/2)+13))/4

b in { (-(105^(1/2)+13))/4, (105^(1/2)-13)/4} 

b in { (-(105^(1/2)+13))/4, (105^(1/2)-13)/4 }

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