8/b+10=4/2b-7

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Solution for 8/b+10=4/2b-7 equation: 


D( b )

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

8/b+10 = (4/2)*b-7 // - (4/2)*b-7

8/b-((4/2)*b)+7+10 = 0

8/b-2*b+7+10 = 0

8*b^-1-2*b^1+17*b^0 = 0

(17*b^1-2*b^2+8*b^0)/(b^1) = 0 // * b^2

b^1*(17*b^1-2*b^2+8*b^0) = 0

b^1

17*b-2*b^2+8 = 0

17*b-2*b^2+8 = 0

DELTA = 17^2-(-2*4*8)

DELTA = 353

DELTA > 0

b = (353^(1/2)-17)/(-2*2) or b = (-353^(1/2)-17)/(-2*2)

b = (353^(1/2)-17)/(-4) or b = (353^(1/2)+17)/4

b in { (353^(1/2)-17)/(-4), (353^(1/2)+17)/4} 

b in { (353^(1/2)-17)/(-4), (353^(1/2)+17)/4 }

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