8/c=8,c=2

Solution for 8/c=8,c=2 equation:

8/c=8.c=2

We move all terms to the left:

8/c-(8.c)=0


Domain of the equation: c!=0

c∈R


We add all the numbers together, and all the variables

8/c-(+8.c)=0

We get rid of parentheses

8/c-8.c=0

We multiply all the terms by the denominator


-(8.c)*c+8=0

We add all the numbers together, and all the variables

-(+8.c)*c+8=0

We multiply parentheses

-8c^2+8=0

a = -8; b = 0; c = +8;
Δ = b2-4ac
Δ = 02-4·(-8)·8
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16}{2*-8}=\frac{-16}{-16}
=1
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16}{2*-8}=\frac{16}{-16}
=-1
$