8/x+1/2=5/3-3/2x

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Solution for 8/x+1/2=5/3-3/2x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

8/x+1/2 = 5/3-((3/2)*x) // - 5/3-((3/2)*x)

(3/2)*x+8/x+1/2-(5/3) = 0

(3/2)*x+8/x+1/2-5/3 = 0

3/2*x^1+8*x^-1-7/6*x^0 = 0

(3/2*x^2-7/6*x^1+8*x^0)/(x^1) = 0 // * x^2

x^1*(3/2*x^2-7/6*x^1+8*x^0) = 0

x^1

(3/2)*x^2+(-7/6)*x+8 = 0

(3/2)*x^2+(-7/6)*x+8 = 0

DELTA = (-7/6)^2-(4*8*(3/2))

DELTA = -1679/36

DELTA < 0

x in { } 

x belongs to the empty set

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