8/x-3-1/10=32/4x-12

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Solution for 8/x-3-1/10=32/4x-12 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

8/x-(1/10)-3 = (32/4)*x-12 // - (32/4)*x-12

8/x-((32/4)*x)-(1/10)-3+12 = 0

8/x-8*x-1/10-3+12 = 0

8*x^-1-8*x^1+89/10*x^0 = 0

(89/10*x^1-8*x^2+8*x^0)/(x^1) = 0 // * x^2

x^1*(89/10*x^1-8*x^2+8*x^0) = 0

x^1

(89/10)*x-8*x^2+8 = 0

(89/10)*x-8*x^2+8 = 0

DELTA = (89/10)^2-(-8*4*8)

DELTA = 33521/100

DELTA > 0

x = ((33521/100)^(1/2)-(89/10))/(-8*2) or x = (-(89/10)-(33521/100)^(1/2))/(-8*2)

x = ((33521/100)^(1/2)-89/10)/(-16) or x = ((33521/100)^(1/2)+89/10)/16

x in { ((33521/100)^(1/2)-89/10)/(-16), ((33521/100)^(1/2)+89/10)/16} 

x in { ((33521/100)^(1/2)-89/10)/(-16), ((33521/100)^(1/2)+89/10)/16 }

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