8/x-3=(-1/4x-12)+2

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Solution for 8/x-3=(-1/4x-12)+2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

8/x-3 = (-1/4)*x-12+2 // - (-1/4)*x-12+2

8/x-((-1/4)*x)-3-2+12 = 0

(1/4)*x+8/x-3-2+12 = 0

1/4*x^1+8*x^-1+7*x^0 = 0

(1/4*x^2+7*x^1+8*x^0)/(x^1) = 0 // * x^2

x^1*(1/4*x^2+7*x^1+8*x^0) = 0

x^1

(1/4)*x^2+7*x+8 = 0

(1/4)*x^2+7*x+8 = 0

DELTA = 7^2-(4*8*(1/4))

DELTA = 41

DELTA > 0

x = (41^(1/2)-7)/(2*(1/4)) or x = (-41^(1/2)-7)/(2*(1/4))

x = 2*(41^(1/2)-7) or x = -2*(41^(1/2)+7)

x in { -2*(41^(1/2)+7), 2*(41^(1/2)-7)} 

x in { -2*(41^(1/2)+7), 2*(41^(1/2)-7) }

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