8/x-3=5/2x+1

Solution for 8/x-3=5/2x+1 equation:

8/x-3=5/2x+1

We move all terms to the left:

8/x-3-(5/2x+1)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: 2x+1)!=0

x∈R


We get rid of parentheses

8/x-5/2x-1-3=0

We calculate fractions


16x/2x^2+(-5x)/2x^2-1-3=0

We add all the numbers together, and all the variables

16x/2x^2+(-5x)/2x^2-4=0

We multiply all the terms by the denominator


16x+(-5x)-4*2x^2=0

Wy multiply elements

-8x^2+16x+(-5x)=0

We get rid of parentheses

-8x^2+16x-5x=0

We add all the numbers together, and all the variables

-8x^2+11x=0

a = -8; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·(-8)·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*-8}=\frac{-22}{-16}
=1+3/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*-8}=\frac{0}{-16}
=0
$