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8/x-5=x+2
We move all terms to the left:
8/x-5-(x+2)=0
Domain of the equation: x!=0We get rid of parentheses
x∈R
8/x-x-2-5=0
We multiply all the terms by the denominator
-x*x-2*x-5*x+8=0
We add all the numbers together, and all the variables
-7x-x*x+8=0
Wy multiply elements
-1x^2-7x+8=0
a = -1; b = -7; c = +8;
Δ = b2-4ac
Δ = -72-4·(-1)·8
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-9}{2*-1}=\frac{-2}{-2} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+9}{2*-1}=\frac{16}{-2} =-8 $
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