8/y+2-3y

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Solution for 8/y+2-3y equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

8/y-(3*y)+2 = 0

8/y-3*y+2 = 0

8*y^-1-3*y^1+2*y^0 = 0

(2*y^1-3*y^2+8*y^0)/(y^1) = 0 // * y^2

y^1*(2*y^1-3*y^2+8*y^0) = 0

y^1

2*y-3*y^2+8 = 0

2*y-3*y^2+8 = 0

DELTA = 2^2-(-3*4*8)

DELTA = 100

DELTA > 0

y = (100^(1/2)-2)/(-3*2) or y = (-100^(1/2)-2)/(-3*2)

y = -4/3 or y = 2

y in { -4/3, 2} 

y in { -4/3, 2 }

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