80+(4+4x)=(6+10x)

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Solution for 80+(4+4x)=(6+10x) equation: 



80+(4+4x)=(6+10x)

We move all terms to the left:

80+(4+4x)-((6+10x))=0

We add all the numbers together, and all the variables

(4x+4)-((10x+6))+80=0

We get rid of parentheses

4x-((10x+6))+4+80=0



We calculate terms in parentheses: -((10x+6)), so:

(10x+6)

We get rid of parentheses

10x+6

Back to the equation:

-(10x+6)



We add all the numbers together, and all the variables

4x-(10x+6)+84=0

We get rid of parentheses

4x-10x-6+84=0

We add all the numbers together, and all the variables

-6x+78=0

We move all terms containing x to the left, all other terms to the right

-6x=-78

x=-78/-6

x=+13

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