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80+(5/16)y=100
We move all terms to the left:
80+(5/16)y-(100)=0
Domain of the equation: 16)y!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
(+5/16)y+80-100=0
We add all the numbers together, and all the variables
(+5/16)y-20=0
We multiply parentheses
5y^2-20=0
a = 5; b = 0; c = -20;
Δ = b2-4ac
Δ = 02-4·5·(-20)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20}{2*5}=\frac{-20}{10} =-2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20}{2*5}=\frac{20}{10} =2 $
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