80-1/3x=1/2x+75

Solution for 80-1/3x=1/2x+75 equation:

80-1/3x=1/2x+75

We move all terms to the left:

80-1/3x-(1/2x+75)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 2x+75)!=0

x∈R


We get rid of parentheses

-1/3x-1/2x-75+80=0

We calculate fractions


(-2x)/6x^2+(-3x)/6x^2-75+80=0

We add all the numbers together, and all the variables

(-2x)/6x^2+(-3x)/6x^2+5=0

We multiply all the terms by the denominator


(-2x)+(-3x)+5*6x^2=0

Wy multiply elements

30x^2+(-2x)+(-3x)=0

We get rid of parentheses

30x^2-2x-3x=0

We add all the numbers together, and all the variables

30x^2-5x=0

a = 30; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·30·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*30}=\frac{0}{60}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*30}=\frac{10}{60}
=1/6
$