80-4((-5)+(1/4y))=100-y

Solution for 80-4((-5)+(1/4y))=100-y equation:

80-4((-5)+(1/4y))=100-y

We move all terms to the left:

80-4((-5)+(1/4y))-(100-y)=0


Domain of the equation: 4y))!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

-4((-5)+(+1/4y))-(-1y+100)+80=0

We get rid of parentheses

-4((-5)+(+1/4y))+1y-100+80=0

We multiply all the terms by the denominator


-4((-5)+(+1+1y*4y))-100*4y))+80*4y))=0

We add all the numbers together, and all the variables

-4((-5)+(1y*4y+1))-100*4y))+80*4y))=0

Wy multiply elements

-1600y^2-4((-5)+(1y*4y+1))=0