80.65+14.08y(0.012106-y)=100-7.27y(1+y)

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Solution for 80.65+14.08y(0.012106-y)=100-7.27y(1+y) equation: 



80.65+14.08y(0.012106-y)=100-7.27y(1+y)

We move all terms to the left:

80.65+14.08y(0.012106-y)-(100-7.27y(1+y))=0

We add all the numbers together, and all the variables

14.08y(-1y+0.012106)-(100-7.27y(y+1))+80.65=0

We multiply parentheses

-14y^2+0.169484y-(100-7.27y(y+1))+80.65=0



We calculate terms in parentheses: -(100-7.27y(y+1)), so:

100-7.27y(y+1)

determiningTheFunctionDomain
-7.27y(y+1)+100

We multiply parentheses

-7y^2-7y+100

Back to the equation:

-(-7y^2-7y+100)



We get rid of parentheses

-14y^2+7y^2+7y+0.169484y-100+80.65=0

We add all the numbers together, and all the variables

-7y^2+7.169484y-19.35=0

a = -7; b = 7.169484; c = -19.35;
Δ = b2-4ac
Δ = 7.1694842-4·(-7)·(-19.35)
Δ = -490.39849917374
Delta is less than zero, so there is no solution for the equation

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